in the first problem its asking me how would i separate the mixtures of KBr and BaSO4
in the second one its asking me, suppose i have a mixture of Mg(OH)2 and BaSO4, how would i separate this mixture.
2007-08-30 16:09:53 · 3 answers · asked by orange_crush_05 6 in Science & Mathematics ➔ Chemistry
Add water and filter. KBr is soluble, BaSO4 is not. BaSO4 will sit on the filter paper, and KBr will go through in the filtrate. Evaporate the filtrate to recover the KBr.
In the second one, add sulfuric acid, the Mg will become MgSO4.
Mg(OH)2 + H2SO4 = MgSO4 + 2 H2O
MgSO4 is reasonably soluble -- you can dissolve that in a lot of water. Then filter off the BaSO4 (the BaSO4 again will stay on the filter paper), and then add NaOH to the filtrate.
MgSO4 + 2 NaOH = Mg(OH)2 + Na2SO4
Now you filter again, but this time the magnesium hydroxide is not soluble, so it sits on the filter paper, whereas sodium sulfate is soluble so it goes through into the filter flask.
Remember -- choose the BEST answer. Don't leave it for the "voters" because then the first answer is automatically chosen!
2007-08-30 16:17:10 · answer #1 · answered by Fly On The Wall 7 · 0⤊ 0⤋
In each couplet you list, one substance is soluble in water and the other is not.
Just add water to dissolve one of them and filter the water solution.
2007-08-30 16:15:29 · answer #2 · answered by reb1240 7 · 0⤊ 1⤋
Organic extraction with a bit of acid.
2007-08-30 16:14:55 · answer #3 · answered by jangy 1 · 1⤊ 2⤋