t=0.2s+10 and 4s+5t=35
its not a graph, you have to solve using substitution..
2007-08-30 16:04:50 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
t = 0.2s + 10 >>>>>>equation 1
4s + 5t = 35 >>>>>>equation 2
From equation 1, t = 0.2s + 10
Subsitute into equation 2.
4s + 5(0.2s + 10) = 35
4s + 1s + 50 = 35
5s = 35 - 50
5s = -15
s = -15 / 5
s = -3
Subsitute s = -3 into equation 1
t = 0.2s + 10
t = 0.2(-3) + 10
t = -0.6 + 10
t = 9.4
Thus s = -3 , t = 9.4
2007-08-30 16:15:31 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Alright, T is given. 0.2s+10. So, you substitute (replace) the T in 4s+5t with the given to. The eqation will then look like 4s+5(0.2s+10)= 35 then you just solve like any other problem.
2007-08-30 23:17:14 · answer #2 · answered by eric b 1 · 0⤊ 0⤋
Substitute (0.2s+10) into where t is in the second equation.
4s+5(0.2s+10)=35
Then simplify by multiplying the numbers in the parentheses by 5.
4s+1.0s+50=35
Simplify more by adding the two s.
5s+50=35
Put all like terms on one side.
5s=35-50
Simplify.
5s=-15
Solve.
s= -3
Now you can go back and solve for t. Just substitute the s you just found into the first equation.
t = 0.2(-3)+10
t=9.4
2007-08-30 23:13:25 · answer #3 · answered by virtuosanina 2 · 0⤊ 0⤋
t = 0.2s + 10 and
4s + 5t = 35
=> 4s +5(0.2s + 10) = 35
=> 4s + s = 35 -- 50
=> s = -- 3
and t = 0.2(-- 3) + 10 = 9.4
2007-08-30 23:11:46 · answer #4 · answered by sv 7 · 0⤊ 0⤋
subsitute t in second eq
4s + 5(0.2s + 10) = 35
4s + s + 50 = 35
5s = -15
s = -3
t = 0.2s + 10 = 0.2 x (-3) + 10 = 9.4
2007-08-30 23:12:21 · answer #5 · answered by norman 7 · 0⤊ 0⤋
You sub the first equation in as t. to get
4s+5(.2s+10)=35
4s+1s+50=35
5s+50=35
5s=-15
s=-3
t=.2s +10
t= -.6 +10
t= 9.4
2007-08-30 23:15:08 · answer #6 · answered by Kat 2 · 0⤊ 0⤋