I want to do this with the "Unit Conversion" method. A vehicle is traveling 15 kmh, how long does it take to go 100 meters in seconds. (I know 15000x=3600(100) x=24s....that's not the question)
I want to know how to do it with "Unit Conversion" method where all the unwanted units cancel out.
i.e.
15km/hr *1000m/Km *hr/3600s ...
I need to set up the fractions in such a way to end up with 100m/24s without having to do anything else. Maybe 100 meters needs to be paired with something else?
2007-08-30
14:56:51
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3 answers
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asked by
RogerDodger
1
in
Science & Mathematics
➔ Physics
I could end up with 100m/24s OR 24s/100m; either way, it doesn't matter.
2007-08-30
14:58:35 ·
update #1
I just answered my own question, maybe you guys are curious:
(100m/1)*(1km/1000m)*(1hr/15km)*(3600s/hr)= 24s
It has something to do with putting what you start with (100m) in the top left
2007-08-30
15:13:43 ·
update #2
(100m/1) * (1km/1000m) * (1hr/15km) * (3600s/1hr) = 24s
2007-08-30
15:15:13 ·
update #3