ball physics!?

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A ball is dropped from rest from a height h above the ground. Another ball is thrown vertically upwards from the ground at the instant the first ball is released. Determine the speed of the second ball if the two balls are to meet at a height h/3 above the ground.

Details please!!!

2007-08-30 14:56:12 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics

1 answers

Use x = (V^2 - V0^2)/(2a)

Set x = -2/3h (first ball), V0 = 0, and a = -g

-2/3h =-V^2/(2g) ---> V =2*sqrt(g/(3h))

2007-08-30 15:10:29 · answer #1 · answered by nyphdinmd 7 · 0⤊ 0⤋