x/5 - x/2= 3 + 3x/10
2007-08-30 14:46:20 · 7 answers · asked by :] 3 in Science & Mathematics ➔ Mathematics
x/5 - x/2 = 3 + 3x/10
(2x - 5x) /10 = 3 + 3x/10
-3x/10 - 3x/10 = 3
-(3x + 3x )/10 = 3
-6x/10 = 3
-3x/5 = 3
-3x = 15
x = 15/-3
x = -5
2007-08-30 14:57:46 · answer #1 · answered by LanHan 1 · 1⤊ 0⤋
1. Make all of the denominators the same:
2x/10 - 5x/10 = 3 + 3x/10
2 Then simplify
-3x/10 = 3 + 3x/10
-6x/10 = 3
3. Solve for x
(-6x/10)(-10/6) = 3(-10/6)
x = -30/6 = -5
2007-08-30 14:57:57 · answer #2 · answered by Michelle M 2 · 0⤊ 0⤋
x/5 - x/2= 3 + 3x/10
Multiply through by 10:
2x - 5x = 30 + 3x
<=> -6x = 30
<=> x = -5.
2007-08-30 14:53:38 · answer #3 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
x/5 -- x/2 = 3 + 3x/10
=> 2x -- 5x = 30 + 3x
=> -- 6x = 30
=> x = -- 5
2007-08-30 14:58:25 · answer #4 · answered by sv 7 · 0⤊ 0⤋
1 st take x/5 and x/2 and make them 2x/10 and 5x/10 to make -3x/10
2nd move 3x/10 to the other side to get -6x/10=3
3rd divide both sides by 3 to get -x/5=1
the answer is -5.
2007-08-30 15:01:34 · answer #5 · answered by lord_andys_new_id 1 · 0⤊ 0⤋
rewrite with common denominator:
(2x/10) -(5x/10)=(30/10)+(3x/10)
(2x-5x-3x)/10=30/10
-6x=30
x= - 5
2007-08-30 14:58:27 · answer #6 · answered by vcs7578 5 · 0⤊ 0⤋
wait hold on...
2007-08-30 14:55:26 · answer #7 · answered by Anonymous · 0⤊ 1⤋