can you please help me!!!??
2007-08-30 13:51:13 · 6 answers · asked by gyrl89 1 in Science & Mathematics ➔ Mathematics
(2x + 1) (x - 5) = 0
x = - 1/2 , x = 5
2007-09-03 11:29:25 · answer #1 · answered by Como 7 · 0⤊ 0⤋
2x^2 -- 9x -- 5 = 0
=> 2x^2 -- 10x + x -- 5 = 0
=> 2x(x -- 5) + 1(x -- 5) = 0
=> (x -- 5)(2x + 1) =0
=> x -- 5 = 0 gives x = 5
and 2x + 1 = 0 gives x = --1/2
2007-08-30 20:56:53 · answer #2 · answered by sv 7 · 0⤊ 0⤋
That's simple:
2x^2 - 9x - 5 = 0
2x^2 - 10x + x - 5 = 0
2x(x - 5) + (x - 5) = 0
(x - 5) (2x + 1) = 0
2007-08-30 21:00:15 · answer #3 · answered by Hell's Angel 3 · 0⤊ 0⤋
2x^2-9x-5=0
factors to
(2x+1)(x-5)
so x= -1/2 or 5
2007-08-30 20:58:09 · answer #4 · answered by tfloto 6 · 0⤊ 0⤋
5*2=10
-10+1 =9
so , you need to write coeffiient 9 as -10+1 (i.e as factors )
2007-08-30 20:58:48 · answer #5 · answered by calculus 1 · 0⤊ 0⤋
2x^2-9x-5=0
(2x+1)(x-5)=0
2x+1=0--->2x=-1-->x=-1/2
x-5=0--->x=5
2007-08-30 20:58:26 · answer #6 · answered by cool j 2 · 0⤊ 0⤋