sin3u=sinu(3-4sin^2u)?

1 ⤊

sin3u=sinu(3-4sin^2u)?

2007-08-30 13:20:54 · 4 answers · asked by deadman 2 in Social Science ➔ Gender Studies

4 answers

sin3u = sinu(3 - 4sin^2u)
sin2u = 3 - 4sin^2u **sin2u = 2sinucosu
2sinucosu = 3 - 4((1-cos2u)/2)
2sinucosu = 1 - 2cos2u
2sinucosu + 2cos2u = 1
2cosu(sinu + cosu) = 1
2cosu = 1 and sinu + cosu = 1 <---- as far as I can get with this one
cosu = ½
u = cos^-1(½)
u = π/3

2007-08-31 09:21:31 · answer #1 · answered by Anonymous · 0⤊ 0⤋

Osta maeeeti.

2007-09-03 18:03:32 · answer #2 · answered by Candy 7 · 0⤊ 0⤋

Three or four.

2007-08-30 21:23:13 · answer #3 · answered by Anonymous · 0⤊ 0⤋

"Now get out of here before I taunt you again"

2007-08-30 21:56:09 · answer #4 · answered by Brooke 3 · 1⤊ 0⤋