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solve for x:
x^2 - 3x - 10 > 0

2007-08-30 13:17:16 · 3 answers · asked by cow 1 in Science & Mathematics Mathematics

3 answers

(x - 5) (x + 2) > 0

Possible solutions:-
x > 5 , x + 2 >0
x > 5 , x > - 2
OR
x - 5 < 0 , (x + 2) < 0
x < 5 , x < - 2

2007-09-03 11:25:49 · answer #1 · answered by Como 7 · 0 0

Factor this into (x - 5) (x+2) > 0

So, the solutions are x = 5, -2

2007-08-30 20:23:59 · answer #2 · answered by thehazmater 2 · 0 0

x^2 - 5x + 2x - 10 > 0
x(x-5)+2(x-5) > 0
(x+2)(x-5) > 0

x+2 and x-5 are both > 0
x > -2 and x > 5
x > 5

OR
x+2 and x-5 are both > 0
x < -2 and x < 5
x < -2

x = {(-inf, -2)U(5, inf)}

2007-08-30 20:23:50 · answer #3 · answered by gudspeling 7 · 0 0

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