Solve and Graph...
2007-08-30 13:13:38 · 7 answers · asked by blessed 1 in Science & Mathematics ➔ Mathematics
3y = 2x + 15 is equation of a straight line.
y = (2/3) x + 5
(0 , 5) and (3 , 7) are points on the line.
Draw a line thro` these points.
2007-08-30 21:53:49 · answer #1 · answered by Como 7 · 1⤊ 0⤋
2x-3y+15=0
just put this equation in the form of a line, y = mx + b:
-3y = -2x - 15
3y = 2x + 15
y = (2x/3) + 5
when you graph it, the y -intercept is positive 5, and go up 2 and over to the right 3 to make a 2nd point on your line
2007-08-30 20:20:02 · answer #2 · answered by peachi517 2 · 1⤊ 0⤋
This is a linear model, meaning y = mx + b,
You want to put it as -3y = - 2x - 15,
which will give you y = 2/3x + 5.
Then you can graph it by finding the y intercept, (-5) and adding points by following the rise/run. Or you could substitute in points to find the equivalent. Such as at x = 0, y = 5.
EDIT: Thanks for catching my mistake in Algebra, poster below me.
2007-08-30 20:19:27 · answer #3 · answered by Anonymous · 0⤊ 0⤋
y=2/3x+5
The answer is a line that intercepts the y-axis at 5 and has a slope of 2/3 which graphed would come out of the y-intercept 2 right and 3 up. So the next graph point you would have would be (2,8) then (4,11); with these points you could graph the line.
2007-08-30 20:23:55 · answer #4 · answered by the_lovely_princess_serena 3 · 0⤊ 1⤋
The answers above discuss how to graph it.
But you can't 'solve' it. There are two unknowns (x and y) but only one equation.
2007-08-30 20:23:26 · answer #5 · answered by SV 5 · 0⤊ 3⤋
i think u make it to
y= -2/3x -5
2007-08-30 20:20:21 · answer #6 · answered by Anonymous · 0⤊ 1⤋
i think its =10xy
2007-08-30 20:17:36 · answer #7 · answered by stranger 3 · 0⤊ 1⤋