How far will a freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/

Question

I need not only the answer, but how to do it so I know how to do it. In an esay to understand explanation please. Thank you.

How far will a freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/s? Sorry, forgot to add the seconds part.

Answer 1

Use kinetic and potential energy

mgh = mv^2 / 2
h = v^2 / (2g)
= 10^2 / (2*9.81)
= 5.1 m
or 5 m if you use g = 10 m/s^2

Answer 2

This is a two-step procedure. For a "rest" position drop,
First, v= a*t, you have v and a, so you find t (about 1 second)
Then x = (a/2)t^2. You have a and t, so find x.
(about 5 meters)

Answer 3

Vf^2 = 2ad + Vi^2

Vf = final velocity (10m/s)
a = accelertion (9.8m/s^2)
d = displacement
Vi = initial velocity (0m/s)

(10)^2 = 2(9.8)d + 0
100 = 19.6d
d =~ 5.1m