If log [little 2 at the bottom] x = 5
what is x?
2007-08-30 13:07:23 · 6 answers · asked by cow 1 in Science & Mathematics ➔ Mathematics
log2 (x) = 5
2^5 = x
x = 32
2007-09-03 11:20:41 · answer #1 · answered by Como 7 · 0⤊ 0⤋
x=2^5
x=32
2007-08-30 13:12:21 · answer #2 · answered by cool j 2 · 0⤊ 0⤋
2^5=32
2007-08-30 13:11:09 · answer #3 · answered by fcas80 7 · 0⤊ 0⤋
x=32
2007-08-30 15:53:01 · answer #4 · answered by hoe sokee 1 · 0⤊ 0⤋
3(2^2x)?10(2^x)+8 = 0 to simplify paintings, we enable y = 2^x 3y² - 10y + 8 = 0 factoring: (3y-4)(y -2) = 0 first element: 3y-4 = 0 3y = 4 y = 4/3 2^x = 4/3 x = log[base2] (4/3) <----- first answer enable this be "a" a = log[base2] (4/3) a = log[base2](4) - log[base2](3) a = log[base2](2^2) - log[base2](3) a = 2log[base2](2) - log[base2](3) a = 2(a million) - log[base2](3) a = 2 - log[base2](3) 2nd element: y-2 = 0 y = 2 2^x = 2 x = a million <----- 2nd answer enable this be "b" b = a million so a+b = 2 - log[base2](3) + a million a+b = 3 - log[base2](3) a+b = 3log[base2](2) - log[base2](3) a+b = log[base2](2^3) - log[base2](3) a+b = log[base2](8) - log[base2](3) a+b = log[base2](8/3) answer: a+b = log[base2] (8/3)
2016-12-12 14:38:21 · answer #5 · answered by Anonymous · 0⤊ 0⤋
log [little b at the bottom] x = m is equivalent to solving b^m = x.
Thus, log [little 2 at the bottom] x = 5 is equivalent to solving 2^5=x.
2007-08-30 13:10:53 · answer #6 · answered by johnvee 3 · 1⤊ 0⤋