By simply adding or subtracting terms appropriately, your expression simplifies to:
30 x^2y - 7 z^2y.
This equals y(30 x^2 - 7 z^2), of course,
PROVIDED that y is a multiplier and NOT part of the exponent. (When ambiguity of interpretation is possible, it is the duty of the question poser to rewrite expressions in such a way that that ambiguity is resolved or clarified.)
That's about all that can be done with it.
[You didn't ASK us to put it equal to zero and SOLVE it. Had you done so, the solutions to y(30 x^2 - 7 z^2) = 0 would have been y = 0 or x/z = +/- sqrt (7/30).]
Live long and prosper.
2007-08-30 12:01:09
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answer #1
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answered by Dr Spock 6
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What's the question?
Does 3x^2y mean (3x)^(2y), or does it mean (3) (x^2) (y) ?
It looks like you have 3x^2y + 9x^2y + 7x^2y + 11x^y + ...
plus 4x^2y - 11z^2y
3 + 9 + 7 +11 = 30
4 - 11 = -7
So it adds up to 30x^2y - 7z^2y = y (30x^2 - 7z^2)
2007-08-30 12:02:30
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answer #2
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answered by morningfoxnorth 6
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you can only combine like terms so you will get no actual number solution...
but you need to follow order of operations too.
I don't know what those ^ are I'm guessing an exponent but i don't know the number but the exponent can be the differnce between a like term and not. so here.......
(3x^2y + 4z^2y) - (-9x^2y + 11z^2y) + (7x^2y + 11x^2y)
=30x^8y - 7z^
3x^2y - (-9x^2y) + (7x^2y + 11x^2y) = 30x^8y
4z^2y - 11z^2y = -7z^
2007-08-30 12:09:16
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answer #3
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answered by 45 3
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(3x^2y + 4z^2y) - (-9x^2y + 11z^2y) + (7x^2y + 11x^2y)
3x^2y + 4z^2y + 9x^2y - 11z^2y + 7x^2y + 11x^2y
Put like terms together to make it easier for you.
3x^2y + 9x^2y +7x^2y + 11x^2y + 4z^2y -11z^2y
(3+9+7+11)x^2y + (4-11)z^2y
30x^2y - 7z^2y
2007-08-30 12:05:24
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answer #4
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answered by Anonymous
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(3x^2y + 4z^2y) - (-9x^2y + 11z^2y) + (7x^2y + 11x^2y)
is like (x^2y)(3-(-9)+7+11) + (z^2y)(4+11)=
y((x^2)(3-(-9)+7+11) + (z^2)(4+11))
2007-08-30 12:02:49
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answer #5
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answered by Anonymous
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3x²y + 4z²y - (-9x²y + 11z²y) + (7x²y + 11x²y) =
3x²y + 4z²y + 9x²y - 11z²y + 7x²y + 11x²y =
(3x²y + 9x²y + 7x²y + 11x²y) + (4z²y - 11z²y) =
20x²y - 7z²y
just group like terms
2007-08-30 12:03:07
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answer #6
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answered by Philo 7
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First get rid of that parentheses by changing the - sign between the first and second sets to a + sign and changing the signs of both expression inside it.
Then just group and add together all the like terms, everything with x^2y gets added as one term and everything with x^2z gets added as the second.
2007-08-30 12:03:48
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answer #7
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answered by Tom K 6
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What is the question? are you supposed to simplify it? Is it supposed to be equal to something, so that you can solve for either x or y?
2007-08-30 12:00:04
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answer #8
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answered by fotoguy 4
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algaebrahelp.com
2007-08-30 12:01:27
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answer #9
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answered by clever1 7
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