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(3x^2y + 4z^2y) - (-9x^2y + 11z^2y) + (7x^2y + 11x^2y)

2007-08-30 11:55:55 · 9 answers · asked by shellyeph 1 in Science & Mathematics Mathematics

9 answers

By simply adding or subtracting terms appropriately, your expression simplifies to:

30 x^2y - 7 z^2y.

This equals y(30 x^2 - 7 z^2), of course,

PROVIDED that y is a multiplier and NOT part of the exponent. (When ambiguity of interpretation is possible, it is the duty of the question poser to rewrite expressions in such a way that that ambiguity is resolved or clarified.)

That's about all that can be done with it.

[You didn't ASK us to put it equal to zero and SOLVE it. Had you done so, the solutions to y(30 x^2 - 7 z^2) = 0 would have been y = 0 or x/z = +/- sqrt (7/30).]

Live long and prosper.

2007-08-30 12:01:09 · answer #1 · answered by Dr Spock 6 · 0 0

What's the question?

Does 3x^2y mean (3x)^(2y), or does it mean (3) (x^2) (y) ?

It looks like you have 3x^2y + 9x^2y + 7x^2y + 11x^y + ...
plus 4x^2y - 11z^2y

3 + 9 + 7 +11 = 30
4 - 11 = -7

So it adds up to 30x^2y - 7z^2y = y (30x^2 - 7z^2)

2007-08-30 12:02:30 · answer #2 · answered by morningfoxnorth 6 · 0 0

you can only combine like terms so you will get no actual number solution...

but you need to follow order of operations too.

I don't know what those ^ are I'm guessing an exponent but i don't know the number but the exponent can be the differnce between a like term and not. so here.......


(3x^2y + 4z^2y) - (-9x^2y + 11z^2y) + (7x^2y + 11x^2y)

=30x^8y - 7z^

3x^2y - (-9x^2y) + (7x^2y + 11x^2y) = 30x^8y

4z^2y - 11z^2y = -7z^

2007-08-30 12:09:16 · answer #3 · answered by 45 3 · 0 1

(3x^2y + 4z^2y) - (-9x^2y + 11z^2y) + (7x^2y + 11x^2y)

3x^2y + 4z^2y + 9x^2y - 11z^2y + 7x^2y + 11x^2y

Put like terms together to make it easier for you.


3x^2y + 9x^2y +7x^2y + 11x^2y + 4z^2y -11z^2y

(3+9+7+11)x^2y + (4-11)z^2y

30x^2y - 7z^2y

2007-08-30 12:05:24 · answer #4 · answered by Anonymous · 0 0

(3x^2y + 4z^2y) - (-9x^2y + 11z^2y) + (7x^2y + 11x^2y)
is like (x^2y)(3-(-9)+7+11) + (z^2y)(4+11)=
y((x^2)(3-(-9)+7+11) + (z^2)(4+11))

2007-08-30 12:02:49 · answer #5 · answered by Anonymous · 0 1

3x²y + 4z²y - (-9x²y + 11z²y) + (7x²y + 11x²y) =
3x²y + 4z²y + 9x²y - 11z²y + 7x²y + 11x²y =
(3x²y + 9x²y + 7x²y + 11x²y) + (4z²y - 11z²y) =
20x²y - 7z²y

just group like terms

2007-08-30 12:03:07 · answer #6 · answered by Philo 7 · 0 1

First get rid of that parentheses by changing the - sign between the first and second sets to a + sign and changing the signs of both expression inside it.

Then just group and add together all the like terms, everything with x^2y gets added as one term and everything with x^2z gets added as the second.

2007-08-30 12:03:48 · answer #7 · answered by Tom K 6 · 0 1

What is the question? are you supposed to simplify it? Is it supposed to be equal to something, so that you can solve for either x or y?

2007-08-30 12:00:04 · answer #8 · answered by fotoguy 4 · 0 0

algaebrahelp.com

2007-08-30 12:01:27 · answer #9 · answered by clever1 7 · 0 1

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