I need help in Algebra 2?

Question

x=24+xy:x=-12
How do you solve?

ok thanks and the lesson is isolate the variable

Answer 1

solve for y:
since x is 12, put in 12 for x in the equation, so
12 = 24 + 12y
next subtract 24 from both sides of the equation becasue you want to get y by itself and whatever you do to one side, u have 2 do to the other. so,
12 (-24) = 24 +12y (-24)
then it comes to
negative 12 = 12y
then divide both sides by 12 to cancel out the multiplication & get y to be alone. so,
negative 12/12 = 12y/12
then it comes out to be
negative 1 = y
so theres ur answer.!!

Answer 2

Well you have to solve for y here. So plug -12 into where the x's are and solve from there. By my estimations it should look like this

-12=24+(-12)y and solving for y should be

y=3

Answer 3

plug in -12 for the x's. solve for y

-12=24+y(-12)

-12=24+-12y

-36=-12y

y=3

Answer 4

x=24+xy:x=-12
I understand this strange notation to mean:
x=24+xy and x = -12. If this is correct, then:
-12 + 24 =(-12)y
-36 = -12 y
y= 3

Answer 5

x=24+xy

x=-12

Replace x with -12 and solve ofr y

- 12 = 24 - 12y

12y - 12 = 24

12y = 36

y = 3

Answer 6

stick -12 into the equation so... -12=24+(-12)(y)
1) subtract 24 and u get -36 = (-12)(y)
2) divide by -12 to get y alone -36/-12=y
3) 3=y

Answer 7

plug in x=-12

-12=24+(-12y)
-36 = -12y
y=-36/(-12)
y=3

Plug into original equation for your check.

Answer 8

x=24+xy x=-12

-12=24+(-12*y)

-36=-12*y

y=3

Solved