Simplify. Assume x represents a positive number sqrt 45x^4
2007-08-30 10:07:12 · 6 answers · asked by vadataborn 2 in Science & Mathematics ➔ Mathematics
sqrt 45x^4
=sqrt (5*9x^4)
=sqrt (5) * sqrt (9x^4)
=sqrt (5) * 3x^2
=3x^2*sqrt (5)
2007-08-30 10:13:18 · answer #1 · answered by Anonymous · 1⤊ 0⤋
sqrt(45x^4) = [sqrt(45)](x^2) = (6.708)x^2
2007-08-30 18:27:37 · answer #2 · answered by John 2 · 0⤊ 0⤋
SQRT(45*x^4), SQRT of (X^^4) = X ^^ 2 so
x^^2 * SQRT (45), SQRT (45) = SQRT ( 5 * 9) = SQRT(5) * SQRT(9) = 3 * SQRT (5)
X^^2 * 3 * SQRT (5), SQRT (5) = 2.236
X^^2 * 3 * 2.236,
6.708 * X^^2
2007-08-30 17:17:37 · answer #3 · answered by petep73 3 · 0⤊ 0⤋
The way you wrote it, order of operations are not clear at all.
I can tell you this much.... if you raise any number to power of 4, it will always be positive. If you take square root of something raised to power of 4, that is the same thing as raising the number to power of 2.
Square root of 45 is 3sqrt(5)
Try expressing the original expression with enough parenthesis so we can tell what's argument of what, and formulate correct order of operations.
2007-08-30 17:14:00 · answer #4 · answered by tkquestion 7 · 0⤊ 0⤋
sqrt(45x^4)
sqrt(5*3*3x^4)
3x^2*sqrt(5)
2007-08-30 17:13:49 · answer #5 · answered by je t'♥ 5 · 0⤊ 0⤋
sqrt(45*x^4)
=x^2*sqrt(45)
=x^2*sqrt(9*5)
=3*x^2*sqrt(5)
2007-08-30 17:11:15 · answer #6 · answered by Ben B 2 · 1⤊ 0⤋