solve for x if angle RQT=180 angle RQS=2x+4 and angle TQS=6x+20?

3 ⤊

could you show me how to work it

2007-08-30 09:42:12 · 2 answers · asked by nisha10mabry 3 in Science & Mathematics ➔ Mathematics

180 = 2x + 4 + 6x + 20
180 = 8x + 24
156 = 8x
x = 19.5

2007-08-30 09:48:58 · answer #1 · answered by Captain Mephisto 7 · 1⤊ 1⤋

RQT is a straight line
S is a point outside of the line

m< RQS + m< TQS = 180

2x + 4 + 6x + 20 = 180
8x + 24 = 180
8x = 156
x = 19.5

2007-08-30 09:50:23 · answer #2 · answered by Anonymous · 2⤊ 2⤋