a brick walkway for,s the diagonal of a squareplayground. the walkway is 24 meters?

Question

how long is one side of the playground and go to nearest tenth

Thanx

Answer 1

well according to Pythagoras, 24 would be considered the hypotenuse of each of the two right angle traingles forming the square playground. So a^2 + b^2 = c^2

c is the hypotenuse and a,b are the 2 other angles (in this case equal).

So, (24m)^2 = a^2 + b ^2

Since a,b are equal then
576 m^2 = 2 a^2 m^2
288 m^2 = a^2 m^2
a = square root of 288 m^2
a = 16.9 m

The length of one side is approximately 17 meters

Answer 2

Pythagoras theorem states that the square of the two sides of a right triangle is equal to the square of the hypotenuse. So, since we have a square:24^2=576/2=288. The square root of 288=17.0 to the nearest tenth. The other answers solved it the same way. Thanx for the 2 points.

Answer 3

The diagonal would cut the playground into isosceles right triangles with the 24 meters as the hypotenuse. 2x²=24²
√2x = 24
x=24/√2 = 17.0meters

Answer 4

24 is the diagonal of a square that dives it into two triangles right angle.
s^2 + s^2 = h^2
2s^2 = 24^2
2s^2 = 576
s^2 = 288
s = Sq Rt 288 = 16.97.....

Answer 5

24^2=576
526/2=288
Square root of 288 = 17.0 to the nearest tenth

Answer 6

The side of a square s = diagonal d *sqrt(2)2
So s = .707d = 16.968 = 17 meters

Answer 7

24^2 = 2a^2

a^2 = 288

a = 12sqrt2 = 17.0m

Answer 8

24m / sqrt of 2 = 16.9731

Answer 9

(2x)^2 = 24
2x = (24)^0.5 = 2(6^0.5)
x = 6^0.5