We are 4 friends who celebrate each others birthday by going away for a couple of days. Normally 3 of us would pay for the 4th's birthday, easy.
On this occasion we are celebrating 2 of our birthdays and having one trip. The question is:
How do we divide up the total cost of the trip so that the 2 people who's birthday it is also contribute equally to each others birthday?
2007-08-30 07:08:54 · 16 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You could use points. Each birthday-trip costs a "point" to the three the birthday isn't and none to the birthday boy/girl.
This is for two birthdays - so there are two lots of "points". Each of the two whose birthday it isn't get 2 points. Each brithday boy/girl gets 1 point - 1 for their non-birthday part of the trip, none for their birthday.
This totals 6 points (3 for each "trip"). So divide the cost by 6 and multiply by the number of points each person has.
Those who are not celebrating their birthdays contribute 2/6, those who are contribute 1/6.
Try it "my way" and what me's way and you should come to the same answer.
2007-08-30 08:25:09 · answer #1 · answered by anthonypaullloyd 5 · 0⤊ 0⤋
Let's say the trip is $120 per person. Since two people are going, the cost is $240. The two not going should each pay the normal third of the cost, or $80 each. But the two going both owe the other $80 between them. Since the trip is equally for both, they should share their third equally as well and pay $40 each.
This works out to 1/6th of the original cost, but the normal 1/3rd of the cost is covered as if only one went on the trip.
Another way to see this is there are 2 trips of $120 each to be funded, totalling $240. Everybody pays the usual third for each trip. Those not going have to pay for both trips -- or $40 x 2 = $80.
But the two birthday friends only have to pay for the others' trip, since their own is the birthday present -- or $40 each.
2007-08-30 14:32:40 · answer #2 · answered by Don E Knows 6 · 0⤊ 0⤋
You want to make sure that over the full year, each of the four people pays the same amount. I presume this year, there will be only three trips since two birthdays were combined?
Let's say each trip costs a total of $900; so in a normal year, a total of $3,600 is spent and each person pays $900 ($300 each for three trips and nothing when it is their birthday).
This year, there will be three trips for a total of $2,700; so each person should pay $675 (2,700/4) during the year. The two people who are celebrating their birthdays together would be paying $300 each on the other two trips (when it wasn't their birthdays); so they each owe $75 on this trip. The other two people would have paid only $300 so far (because each would have received a free trip on their birthday); so they each owe $375 this time. ($375+$375+$75+$75 = $900), and each person would have paid 1/4 of the annual cost of the three trips.
2007-08-30 14:24:49 · answer #3 · answered by Kathryn 6 · 0⤊ 0⤋
1.) Divide the total cost in two. For example, the total cost is £600 for the one trip. Then treat it as two seperate birthdays; Birthday for friend 1: £300 split evenly between friends 2,3 and 4 = £100 each.
Birthday for friend 2: £300 split evenly between friends 1,3 and 4 = £100 each.
So Friend 1 pays: £100
Friend 2: £100
Friend 3: £200
Friend 4: £200
Friends 3 and 4 pay more because its not their birthday!!
Hope that helps!!!
2007-08-30 14:29:28 · answer #4 · answered by what_me? 2 · 0⤊ 0⤋
You want the two to pay a share of all 4 and 2 of you to only pay for 3. That is 4 shares +4 shares + 3 shares +3 shares = 10 shares
So two of you will pay 4/10 = 2/5 of the cost while the other two will pay 3/10 of the cost
2007-08-30 14:20:46 · answer #5 · answered by chasrmck 6 · 0⤊ 0⤋
Those with no birthday have shares of 2s, while the birthday friends have shares of s, since one of the shares is foregone as celebration. So the total shares are 2*2s + 2*s = 6s.
Those with birthdays pay s/6s = 1/6, while those without pay 2s/6s = 1/3
2007-08-30 14:18:06 · answer #6 · answered by John V 6 · 1⤊ 1⤋
divide by three. each of the 2 friends not having birthdays pay a third. the remaining 2 people split the other third. each birthday person pays a sixth.
2007-08-30 14:16:30 · answer #7 · answered by timdoas 3 · 1⤊ 1⤋
Each birthday person pays 1/12.
Other two pays 5/12.
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2007-08-30 14:36:39 · answer #8 · answered by oregfiu 7 · 0⤊ 1⤋
3 pay for the holiday and the 4th person pays for a wild night for all starting off with a trip on a boat, a meal, then lots of drink, clubbing, peep shows, prostitutes and a kebab each
2007-08-30 14:22:31 · answer #9 · answered by Anonymous · 0⤊ 0⤋
Divide everything equally between the 4 friends. Anything different is just too complicated to worry about.
2007-08-30 14:14:03 · answer #10 · answered by oxymoron1992 2 · 1⤊ 0⤋