Polynomial Fractorization Help!!??!?

Question

Solve: Round any irrational solutions to the nearest thousandth:

-t^2 - 16t- 64=0

Answer 1

Get rid of leading (-) by multiplying entire eq. by -1:

t^2+16t+64=0
(t+8)(t+8)=0
t=-8

Answer 2

DO this first:


-t^2 - 16t- 64=0

Get the negative sign out

-(t^2 + 16t +64)

Now...following: ax^2 + bx + c = 0

Multiply a term * c term.

a = -1
c = -64

a * c = 64

Factors of 64 which when subtracted give you the middle b term the16)

1 * 64
2 * 32
4 * 16
8 * 8

8 and 8 when added give you 16.
-(t+8)(t+8)
(-t -8)(t+8)
-t^2 -8t - 8t - 64
-t^2 -16t - 64

voila the factored form is: -(t+8)(t+8)

Answer 3

ok, you would not need to round anything since they already tell you to factor...

This is the way I do it:

so, -t^2 - 16t - 64 = 0

You would use the "sum, product" method, cant really explain it now, but this is it...

so two numbers that add to -16 and multiply to -64...

Well, that is impossible. Therefore, I'm afraid the equation cannot be factored any further than this:

-t(t - 16) = 64

But if you make the entire equation positive, then the factorazation would be simple:

t^2+16t+64=

(t+8)(t+8)=

(t+8)^2

so since we reversed from negative to positive, then the value of t would be opposite to that of the equation, so it would be negative.

Now t=-8

Answer 4

-t^2 - 16t- 64=0
t^2+16t+64 =0
(t+8)^2 =0
t+8 = 0
t= -8