You need to draw each line, which you can probably do most easily if you express them in slope-intercept form.
x - 2y = 8 ==> 2y = x - 8 ==> y = (1/2)x - 4
x + y = -1 ==> y = -x - 1
Just draw these two lines carefully, and you should be able to locate their intersection. It should be (2, -3).
2007-08-30 06:25:04
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answer #1
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answered by DavidK93 7
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x-2y= 8
y= x/2-4 (1)
x+y= -1
y= -x-1 (2)
Draw out graphs (1) and (2). Since they're both obviously straight line graphs (as they are in the form of y=mx+c where c is a constant), just substitute in about 3 values of x to find corresponding values of y, then plot.
The intersection, ie (2, -3), of the two graphs is the solution of the equation. (ie, x=2, y=3)
2007-08-30 06:30:31
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answer #2
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answered by Sarah 1
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x -2y = 8
x + y = -1
The solution is where the lines cross is ( 2, -3 )
One line x - 2y = 8 has these 2 points ( 0, -4) and ( 8, 0 )
Other line x + y = -1 has these 2 points ( 0, -1) and ( -1, 0 )
These 2 lines cross at ( 2, -3 )
2007-08-30 06:35:30
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answer #3
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answered by Will 4
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That just means graph the lines and see where they cross
first you'll need to put the equations above in slope intercept form by solving for y
y = mx + b
so the first equation would be y= 1/2x+4
2007-08-30 06:26:41
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answer #4
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answered by Allen N 2
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