I'm not sure how to solve for a variable if it is in both the numerator and the denominator.
For example: Solve for y, x=(y+2)/(5y-1)
If you could show how to solve this it would be really helpful. Thanks in advance!
2007-08-30 05:59:19 · 6 answers · asked by laura m 1 in Science & Mathematics ➔ Mathematics
x = (y+2)/(5y-1)
x(5y-1) = y + 2
5xy - x = y + 2
5xy - y = x + 2
(5x-1)y = x + 2
y = (x+2)/(5x-1)
2007-08-30 06:10:44 · answer #1 · answered by Philo 7 · 5⤊ 0⤋
You first need to multiply both sides of the equation by (5y - 1), to remove the denominator. After that it's straightforward:
x(5y - 1) = y + 2, so that y(5x - 1) = x + 2, implying that
y = (x + 2) / (5x - 1).
Live long and prosper.
2007-08-30 06:07:56 · answer #2 · answered by Dr Spock 6 · 1⤊ 1⤋
Clear it of fractions first my mutliplying by the common denominator or in this case the denominator.
x(5y-1)=y+2
5xy - x
-x-2 = y-5xy
..........y(1-5x)
-(x+2)/(1-5x) = y
or
(x+2)/(5x-1) = y
2007-08-30 06:08:33 · answer #3 · answered by chasrmck 6 · 1⤊ 0⤋
ok, it extremely is the place you pay interest. you purely ought to assessment something and care with regard to the form you purchased the respond. x/(x - 9) + x/(x - 9) = a million you desire to do away with all fractions. it extremely is comprehensive with the aid of multiplying the two sides with the aid of (x - 9). That leaves us with (x - 9) [ x/(x - 9) + x/(x - 9) ] = (x - 9) [ a million ] See what I did there? I prolonged the two sides with the aid of (x - 9), and positioned the present stuff in sq. brackets to make it clean. whilst we multiply the left hand area with the aid of (x - 9), the denominators cancel out for being the comparable (in basic terms like 9 * (a million/9) cancels the 9). [x + x] = x - 9 Now, remedy for x as prevalent. x + x = x - 9 2x = x - 9 Subtract the two sides with the aid of x, x = -9
2016-10-17 07:20:10 · answer #4 · answered by giardina 4 · 0⤊ 0⤋
x = (y + 2)/(5y - 1)
cross multiply
x(5y - 1) = y + 2
5xy - x = y + 2
5xy - y = x + 2
y(5x - 1) = x + 2
y = (x + 2)/(5x - 1)
2007-08-30 06:15:16 · answer #5 · answered by mohanrao d 7 · 0⤊ 0⤋
5xy-x=y + 2
Since you are dealing with 2 variables and you have only 1 equation, thats all I can think of...
You can also further develop that, and get y's value expressed as x's, but you can never get the value of those 2 variables.
2007-08-30 07:34:38 · answer #6 · answered by Anonymous · 0⤊ 1⤋