How do I complete the square for this expression:
(x^2 + 10x)
2007-08-30 02:16:50 · 4 answers · asked by chrizzle08 2 in Science & Mathematics ➔ Mathematics
x^2 + 10x + 25
You need to take half of the coefficient of x and square it. The coefficient is 10, half of that is 5, and its square is 25. We now have the square of (x + 5).
2007-08-30 02:20:50 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
x^2 + 10x+25=(x+5)^2
2007-08-30 09:20:45 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Since (ax)^2 + 2abx + b^2 = (ax + b)^2
Fit the above into your question we have :
a=1
2*a*b=10, hence b=10/(2*a)=10/(2*1)=5
Now substitute the values of a and b in we have :
a^2 + 2*5*x + 5^2 = (a+5)^2
Hope that helps =D
2007-08-30 09:26:29 · answer #3 · answered by Anonymous · 0⤊ 0⤋
What do you mean by "complete" ??
The expression can be rewritten x(x+10) , which means that the roots are 0 and -10. Is that what you are looking for ?
2007-08-30 09:23:04 · answer #4 · answered by Christophe G 4 · 0⤊ 0⤋