Mary leaves San Francisco and travels toward Los Angeles at 50 mi/h. An hour later, Phil leaves Los Angeles a

Question

and travels toward San Francisco at 60 mi/h. If the two cities are 380 miles apart, how many hours will it take for Mary to meet Phil? Write an algebraic equation and solve.

Answer 1

Mary 50 mph
Phil 60 mph

After 1 hour:-
Mary travels 50 miles
Distance apart = 330 miles

RELATIVE speed of Phil to Mary = 110 mph
Time before they meet = 330 / 110 h = 3 h

They will meet 4 hours after Mary starts off.

Answer 2

4

Answer 3

distance travelled by mary in 1 hour=50*1=50 miles.
let at 'x' distance from san mary meets phil.let 't' be the time taken by phil to meet mary.
x=50+50*t
380-x=60*t
380=50+110t
t=3 hours.
mary takes (1+3) hours to meet phil.
ans is 4 hours.

Answer 4

The easiest way to resolve this is to express the distance of each one of them from a similar point starting at a similar time.
If you consider t=0, the time at which Phil leaves LA, then the distance between Mary and LA is
M = 330 - 50t
because at t=0 she already ahs traveled for an hour so she only has 330 more miles to go and she gets closer to LA at 50 mile/hour.
The distance between Phil and LA is:
P = 60t
because at t=0 he is in LA and he gets away from LA at a speed of 60miles/h.

They will meet when M = P or 330 - 50t = 60t or 330 = 110t which means when t = 3 hours after Phil's departure (or 4 hours after Mary's departure).

Answer 5

Assume, they will meet t hours after Mary starts. In that time, Mary will travel, 50t miles and Phil will travel 60(t-1) mile.
So,
50t +60(t-1)=380
110t=440
t=4
4 hours after mary starts.

Answer 6

4 hours 20 minutes

Answer 7

FOUR HOURS