2007-08-29 19:30:37 · 8 answers · asked by Nia 3 in Science & Mathematics ➔ Mathematics
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Whenever you have a question like this just go to Google's search engine.
Your question can then be typed as "93 inches in feet" in the search box.
Instead of searching for websites, google does the conversion for you.
This is one of many secret tools you can use on Google.
The answer Google gives is this:
93 inches in feet
93 inches = 7.75 feet
2007-08-29 19:44:16 · answer #1 · answered by Mika 4 · 0⤊ 0⤋
answer: 7 3/4 feet
there are 12 inches in a foot. divide 93 by that
2007-08-29 19:36:03 · answer #2 · answered by missann2000watts 2 · 1⤊ 0⤋
Dear Nia?
There are 12 inches for 1 feet. That means if you divide the number of inches by 12 you get it in feets. So the answer is 93/12=7.75
2007-08-29 19:52:13 · answer #3 · answered by Naughty Naveen 1 · 0⤊ 0⤋
This Site Might Help You.
RE:
how many feet is 93 inches? It's for class?
2015-08-06 16:24:26 · answer #4 · answered by Anonymous · 0⤊ 0⤋
This one is simple. There are 12inches in a foot. So 93inches divided by 12 is 7.75feet. or 7 feet 9 inches. as 12/100x75=9
I hope that has helped you with your studies. Best of luck with your homework.
2007-08-29 19:43:59 · answer #5 · answered by Jo 2 · 0⤊ 0⤋
1 ft = 12 inches,
93 inches = 93/12 ft = 7.75 ft
2007-08-29 19:38:55 · answer #6 · answered by Yusuf 4 · 0⤊ 0⤋
12 ins = 1ft
93 ins = 7 ft 9 ins = 7 ¾ ft
2007-08-29 20:46:27 · answer #7 · answered by Como 7 · 2⤊ 0⤋
7 and 3/4ths
You simply devide by 12 3/4rths of a foot is 9 inches.
2007-08-29 19:35:03 · answer #8 · answered by Anonymous · 0⤊ 0⤋
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Well, to be classified as anorexic you have to be at least 15% below your ideal weight. (you CAN still be anorexic at a normal weight because nervosa is a mental illness though) So the ideal weight for a person who is 5 foot 4 is about 110-115 pounds. 15% of that is 16.5 pounds so 110-16.5 pounds is around 93.5 pounds.
2016-03-27 02:59:29 · answer #9 · answered by Anonymous · 0⤊ 0⤋
7'9 feet
2007-08-29 19:34:53 · answer #10 · answered by Anonymous · 0⤊ 0⤋