12;
x; unicycles
y; bicycles
x; tricycles
y = x + 88
y = z + 40
z = 5x
Substitute in 5x for z
y = x + 88
y = 5x + 40
-5(y = x + 88)
-5y = -5x -440
y = 5x + 40
Add the system of equations together
-4y = -400
Divide by -4
y = 100
Substitute back into original equations;
y = x + 88;
100 = x + 88
Subtract 88
x = 12
y = z + 40;
100 = z + 40
Subtract 40
z = 60
z = 5x;
60 = 5x
Divide by 5
x = 12
This matches with the value of x we got previously, therefore, the company had 12 unicycles.
Hope this helps!
: )
2007-08-29 19:14:17
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answer #1
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answered by God 3
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Let the number of unicycles, bicycles and tricycles be called u, b and t respectively.
b = u + 88
t = 5u
b = t + 40
Substituting the third equation into the first, we have:
t + 40 = u + 88 ==> t = u+48
The second tells us, then, that:
u + 48 = 5u ==> 4u = 48 ==> u = 12
Putting this into the first equation gives b = 88 + 12 = 100
and from the third:
100 = t + 40 ==> t = 60
so u = 12, b = 100, t = 60
2007-08-29 19:14:32
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answer #2
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answered by Anonymous
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Step 1 - Assign some variables:
# unicycles = x
# bicycles = y
# tricycles = z
Step 2 - Establish relationships:
y = x + 88
z = 5x
y = z + 40
Step 3 - Substitutions:
Substitute x = z/5 into y = x + 88 to get:
y = (z/5) + 88
Substitute z = y - 40 into the above eqn. to get:
y=[(y - 40)/5] + 88
Only one value of y satisfies this eqn: 100
Final Step:
Plug this value of y into y = x + 88 to get an answer of 12.
2007-08-29 19:21:27
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answer #3
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answered by Jeffrey Theta 1
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Let, Unicycles = x
Then, Bicycles = x + 88
And, Tricycles = 5x
Bicycles - Tricycles = 40
Therefore, x + 88 - 5x = 40
-4x = -48
x = 12
So, the company made 12 Unicycles last week.
2007-08-29 19:16:31
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answer #4
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answered by seminewton 3
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To answer, break down the words into math equations.
88 more bicycles than unicyles = B(bicycles) = U(unicyles) +88
5 times more tricycyles than unicyles=
T(tricycles) = 5U
40 more bicycles than tricycles= B= T+40
therefore
B= T+40=U +88
therefore
T+40=U+88
therefore
T=U +88 - 40= U +48
remember that T also equals 5U, therefore
T=5U=U +48
therefore
5U - U =48
therefore
4U=48
therefore
U=48/4=12
there are twelve unicycles
2007-08-29 19:19:26
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answer #5
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answered by Nightfall 2
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Let U be number of unicycles
Then 88+U= number of bicycles
5U= number of tricycles.
We also know that 88+U= 40+5U (40+tricycles= bicycles), then U=12. The rest works out.
2007-08-29 19:19:10
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answer #6
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answered by cattbarf 7
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Let u = no. of unicycles, t = no. of tricycles, b = no. of bicycles.
t = 5u
b = u + 88
b = 5u + 40
u + 88 = 5u + 40
48 = 4u
u = 12
Answer: 12 unicycles
t = 5 * 12 OR 60
b = 60 + 40 OR 100
Proof:
60 + 40 = 12 + 88
100 = 100
2007-08-29 19:30:56
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answer #7
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answered by Jun Agruda 7
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b=88+u
t=5u
b=t+40
B=5u+40
88+u= 5u+40
-u -40
48= 4u
/4 /4
12=u
12 unicycles
2007-08-29 19:17:22
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answer #8
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answered by Kat 2
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x, y and z be uni, bi and tri,
y = x + 88
z = 5x
y = z + 40
x + 88 = z + 40
x - z = -48
substitute, z = 5x
x - 5x = -48
x = 12
they have 12 unicycles.
2007-08-29 19:14:59
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answer #9
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answered by Anonymous
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