English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

bike company makes unicycles, bicycles, and tricycles. last week they made 88 more bicycles than unicycles, and 5 times as many tricycles as unicycles. if they made 40 more bicycles than tricycles, how many unicycles did they have.

pleez help!

2007-08-29 19:08:08 · 9 answers · asked by Anonymous in Science & Mathematics Mathematics

9 answers

12;

x; unicycles

y; bicycles

x; tricycles

y = x + 88
y = z + 40
z = 5x

Substitute in 5x for z

y = x + 88
y = 5x + 40

-5(y = x + 88)

-5y = -5x -440
y = 5x + 40

Add the system of equations together

-4y = -400

Divide by -4

y = 100

Substitute back into original equations;

y = x + 88;
100 = x + 88

Subtract 88

x = 12

y = z + 40;
100 = z + 40

Subtract 40

z = 60

z = 5x;

60 = 5x

Divide by 5

x = 12

This matches with the value of x we got previously, therefore, the company had 12 unicycles.

Hope this helps!

: )

2007-08-29 19:14:17 · answer #1 · answered by God 3 · 0 0

Let the number of unicycles, bicycles and tricycles be called u, b and t respectively.

b = u + 88
t = 5u
b = t + 40

Substituting the third equation into the first, we have:

t + 40 = u + 88 ==> t = u+48

The second tells us, then, that:

u + 48 = 5u ==> 4u = 48 ==> u = 12

Putting this into the first equation gives b = 88 + 12 = 100

and from the third:

100 = t + 40 ==> t = 60

so u = 12, b = 100, t = 60

2007-08-29 19:14:32 · answer #2 · answered by Anonymous · 1 0

Step 1 - Assign some variables:
# unicycles = x
# bicycles = y
# tricycles = z

Step 2 - Establish relationships:
y = x + 88
z = 5x
y = z + 40

Step 3 - Substitutions:
Substitute x = z/5 into y = x + 88 to get:
y = (z/5) + 88
Substitute z = y - 40 into the above eqn. to get:
y=[(y - 40)/5] + 88

Only one value of y satisfies this eqn: 100

Final Step:
Plug this value of y into y = x + 88 to get an answer of 12.

2007-08-29 19:21:27 · answer #3 · answered by Jeffrey Theta 1 · 0 0

Let, Unicycles = x
Then, Bicycles = x + 88
And, Tricycles = 5x

Bicycles - Tricycles = 40

Therefore, x + 88 - 5x = 40
-4x = -48
x = 12

So, the company made 12 Unicycles last week.

2007-08-29 19:16:31 · answer #4 · answered by seminewton 3 · 0 0

To answer, break down the words into math equations.
88 more bicycles than unicyles = B(bicycles) = U(unicyles) +88
5 times more tricycyles than unicyles=
T(tricycles) = 5U
40 more bicycles than tricycles= B= T+40
therefore
B= T+40=U +88
therefore
T+40=U+88
therefore
T=U +88 - 40= U +48
remember that T also equals 5U, therefore
T=5U=U +48
therefore
5U - U =48
therefore
4U=48
therefore
U=48/4=12
there are twelve unicycles

2007-08-29 19:19:26 · answer #5 · answered by Nightfall 2 · 0 0

Let U be number of unicycles
Then 88+U= number of bicycles
5U= number of tricycles.
We also know that 88+U= 40+5U (40+tricycles= bicycles), then U=12. The rest works out.

2007-08-29 19:19:10 · answer #6 · answered by cattbarf 7 · 0 0

Let u = no. of unicycles, t = no. of tricycles, b = no. of bicycles.

t = 5u
b = u + 88
b = 5u + 40

u + 88 = 5u + 40
48 = 4u
u = 12

Answer: 12 unicycles

t = 5 * 12 OR 60
b = 60 + 40 OR 100

Proof:
60 + 40 = 12 + 88
100 = 100

2007-08-29 19:30:56 · answer #7 · answered by Jun Agruda 7 · 3 0

b=88+u
t=5u
b=t+40

B=5u+40
88+u= 5u+40
-u -40
48= 4u
/4 /4
12=u

12 unicycles

2007-08-29 19:17:22 · answer #8 · answered by Kat 2 · 0 0

x, y and z be uni, bi and tri,

y = x + 88
z = 5x
y = z + 40

x + 88 = z + 40
x - z = -48
substitute, z = 5x
x - 5x = -48
x = 12

they have 12 unicycles.

2007-08-29 19:14:59 · answer #9 · answered by Anonymous · 1 0

fedest.com, questions and answers