Need help in Algebra please...?

Question

Factor Completely.

1) ax+bx-a-b

2) c^3+c^2d^2-cd-d^3

Thank you so much.=)

Answer 1

1) ax -a +bx-b
= a(x-1) + b(x-1)
= (a+b)(x-1)


2) from formula : (c^3 - d^3) = (c-d) (c^2 +cd+d^2)
c^3+c^2d^2-cd-d^3
=c^3 - d^3+c^2d^2-cd
= (c-d) (c^2 +cd+d^2) + cd(cd-1)

I am not sure bout q2 but most probably correct

Answer 2

I hope I'm right.. it's been a while since I've done algebra, but here goes.

1) ax+bx-a-b = 2x
ax plus bx equals 2x+a+b
2x+a+b -a = 2x+b
2x+b-b= 2x
Here what you have to do is add the algebraic numerals first so ax+bx = 2xab then we have to minus the a and b which leaves us with 2x.


2)c^3+c^2d^2-cd-d^3 = c^4d^-2
c^3+c^2d^2= c^5d^2-cd-d^3 = c^4d^-2
Here what I have done is added the algebraic numerals together so c^3+c^2d^2 = c^5d^2. Then I minused the cd and d^3 which left me with c^4d^-2..

I hope that helps.. it all seems like I'm talking japanese even to me. I hope I'm right for your sake. Good luck with the homework.

Answer 3

1. Rearrange to a(x-1)+b(x-1) = (x-1)(a+b)
2. cd(cd-1)+(c^3-d^3)=cd(cd-1)+(c-d)*(c^2+cd+d^2)
There may be better ways to do this, but this does treat the difference of cubes.