for a number like
xy.zlmn
or
abc.def
1 significant figure
x0 or
a00
2 significant figures
xy or
ab0
3 significant figures
xy.z or
abc
4 significant figures
xy.zl or
abc.d
etc....
2007-08-29 17:55:03
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answer #1
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answered by Anonymous
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Depends on what you're trying to achieve....It has been a while since I've been in a similar situation of having to sort out significant digits. Here are some possible answers:
Answer 1: If you round to 10 in all cases, you will have TWO digits left, both of which are significant.
Answer 2: If you leave the numbers "as-is" you can count the last two digits as significant, even though there are three digits.
Answer 3: add an extra zero after the decimal point.
Answer 4: Try putting the numbers in "exponential" format, e.g. 1.00 x 10^1 (where "^" means "raised to the power of"), 1.01 x 10^1, etc., and take it from there.
2007-08-29 17:58:41
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answer #2
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answered by porirua_aspie 1
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If you want to round 10.1 to 2 signigicant figures you need to write 10.
If you write 10 this will only be 1 significant figure, the writing of the decimal point is required under technical significant figure rules.
You could also write 1.0 * 10^1
2007-08-29 17:56:13
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answer #3
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answered by bzim03 4
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It would be 10. The figures between the first number and the decimal are significant even though the decimal disappears when you round it.
ex.
010.3 = 10
1003.0004 = 1003
2007-08-29 17:52:47
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answer #4
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answered by atjetcmk 3
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Use scientific notation:
10 = 1.0E1
this equals 10, rounded to one decimal place and two significant digits.
2007-08-29 17:55:04
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answer #5
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answered by R_Crumb_Rocks 4
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Significant figures are determined by the right-most digit, not the number of digits that are non-zero. 10 is correct, since it covers the range from 9.5 to 10.5.
2007-08-29 17:53:08
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answer #6
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answered by cattbarf 7
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10.0 is the same as 10.
2007-09-02 11:39:41
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answer #7
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answered by johnandeileen2000 7
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they already are 2 sig figs
btw u cant get more precise answer than u started with
2007-08-29 17:51:27
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answer #8
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answered by Man of Ideas 5
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sorry i don't know
2007-08-29 17:50:25
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answer #9
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answered by Anonymous
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