math help please?

0 ⤊

how would you solve this

2+ (the square root of) 3x-6 = x

2007-08-29 16:40:00 · 2 answers · asked by Anonymous in Education & Reference ➔ Homework Help

(the square root of) 3x-6 = x - 2
[(the square root of) 3x-6]^2 = [x - 2]^2
3x-6 = [x - 2]^2
3(x-2)=(x-2)^2
3 = x - 2
x = 5

2007-08-29 16:51:39 · answer #1 · answered by Jandro 1 · 0⤊ 0⤋

2+ (the square root of) 3x-6 = x

so (the square root of) 3x-6 = x -2

3(x-2) = (x-2) (x-2)

so 3 = x-2

x = 5

2007-08-29 23:47:01 · answer #2 · answered by Beardo 7 · 0⤊ 0⤋