(x+2)^2 + 5 = (x+3)^2
please try to show step by step. THANK YOU!
2007-08-29 15:32:46 · 4 answers · asked by fiori3092 3 in Science & Mathematics ➔ Mathematics
to everyone, i did try doing this problem a lot of times
2007-08-29 15:56:27 · update #1
(x+2)^2 + 5 = (x+3)^2
x^2 + 4x + 4 + 5 = x^2 + 6x + 9
4x+9 = 6x + 9
-2x = 0
x = 0
2007-08-29 15:37:58 · answer #1 · answered by way2hot2becool 3 · 1⤊ 0⤋
The first step is to expand the quadratics:
(x+2)^2 = (x+2)(x+2) = x^2 + 2x + 2x + 4 = x^2 + 4x + 4
and (x+3)^2 = x^2 + 6x + 9 similarly. So we have
x^2 + 4x + 4 + 5 = x^2 + 6x + 9
Grouping x terms we get
x^2 - x^2 + 4x - 6x = 9 - 5
<=> -2x = 4
<=> x = -2.
2007-08-29 22:38:43 · answer #2 · answered by Scarlet Manuka 7 · 1⤊ 0⤋
(x+2)(x+2)+5=(x+3)(x+3)
x^2+4x+4+5=x^2+6x+9
4x+9=6x+9
4x=6x
x=0
2007-08-29 22:39:13 · answer #3 · answered by Cameron C. 4 · 0⤊ 0⤋
Lucky girl, lazy girl, stupid girl -
i wish i could have done this when i was in school. But i had nobody to help me You have the world on the internet to help you. But don't abuse your advantages. First try to crack every problem yoursef
2007-08-29 22:41:43 · answer #4 · answered by stratotanker 2 · 0⤊ 1⤋