6[x-(2x+3)]=8-5x
=> 6[x-2x-3]=8-5x
=> 6[-x-3]=8-5x
=> -6x-18=8-5x
=> -6x+5x=8+18
=> -x=26
=>x= -26 ans
2007-08-29 15:15:34
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answer #1
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answered by Anonymous
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First of all, try to get rid of all the brackets...
6(x - 2x -3) = 8 - 5x
6x -12x - 18 = 8 -5x
Now, group the unknown one one side and the rest on the other side...
6x -12x + 5x = 8 + 18
-x = 26
x = -26
2007-08-29 15:16:15
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answer #2
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answered by Roger 4
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Attack the left side first: [x-(2x+3)] . That is a package: Nothing to multiply... the "()'s are meaningless. x - 2x + 3 = -x+3. Now, that mess is multiplied by 6 to yield
-6x + 18 (for the left side) = 8 - 5x
Add 5x to each side: -x + 18 = 8
Subtract 18 from each side: -x = -10
Multiply by -1: x = 10
2007-08-29 15:22:39
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answer #3
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answered by Richard S 6
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Simplify.
6x - 6(2x+3) = 8 - 5x
-12x - 18 = 8 - 11x
Isolate the variable.
-26 = x
x = -26
2007-08-29 15:14:16
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answer #4
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answered by Matiego 3
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6[x-(2x+3)]=8-5x
6x - 12x - 18 = 8 - 5x
6x - 12x + 5x = 8 + 18
-x = 26
x = -26
2007-08-29 15:14:44
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answer #5
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answered by robertonereo 4
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6[x-(2x+3)] = 8 - 5x
6x - 6(2x-3) = 8 -5x
6x -12x - 6(-3) = 8 - 5x
6x - 12x +18 = 8 -5x
6x - 12x +18 - 8 = 8 - 5x - 8
6x -12x + 10 = -5x
6x -12x +10 - 6x = -5x -6x
-12x +10 = -11x
-12x +10 + 12x = -11x + 12x
10 = x
2007-08-29 15:24:41
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answer #6
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answered by The First Dragon 7
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6[x - (2x + 3)] = 8 - 5x
6[x - 2x - 3] = 8 - 5x
6x - 12x - 18 = 8 - 5x
11x - 12x = 26
x = -26
2007-08-29 15:13:01
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answer #7
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answered by Anonymous
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6[x-(2x+3)]=8-5x
6[-x-3]-8+5x=0
-6x-18-8+5x=0
-18-8=6x-5x
-26=x
2007-08-29 15:14:11
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answer #8
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answered by crapcrusader 2
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