Please help me again this math is a killer!!!!!!!?

Question

Find the base b and the height h of a triangle with an area of 10 square feet if its base is 19 feet longer than its height. (Note: The area of a triangle = (bh)/ 2.)
b = ft
h = ft

Answer 1

h = 1 and b = 20

Answer 2

its base is 19 feet longer than its height, you can put that into an equation like this,
B = H +19

so now plug this information into the equation for the area of a triangle.

BH/2 =10
H+19(H) /2=10

distribute the H to H+19

H^2 + 19H / 2 = 10

multiply each side by two
H^2 + 19H = 20

subtract 20 from both sides so you can factor

H^2 + 19H - 20 = 0
if you factor, you get:
(H + 20) (H-1)

so H = -20 or 1.
since distance can't be negative, your only choice for height is 1.

if your base is 19 more than your height, 19+1 = 20
20 is your base.

H = 1 foot
B = 20 feet

Answer 3

just express those relationship in b

b x h/2 = 10
b x h = 20

b=h + 19 (itsd base is 19 feet longer than its height)

(h+19) x h = 20

solve this quadratic equation and you get the answer easily