ok, i really, need helpw with these two geometry questions. theyre supposed to be proofs, but i just need the steps it takes to get the right answer.
GH= z+6
EH= 2z - 4
GE= z
no clue how to set it up, i had (z+6)+(2z-4)=z but that didnt wrk...
and:
m<1= 7x + 3
m<2= 6x + 7
couldnt solve it
please help! thanks!
2007-08-29 13:52:32 · 3 answers · asked by Shorty 2 in Science & Mathematics ➔ Mathematics
Can only guess that GHE is an isosceles triangle with base z and side 2z-4 and z+6. If so, then z+6=2z-4 so z =10
So z=6 = 16 and 2z-4 = 16.
m<1= 7x + 3
m<2= 6x + 7
The above makes no sense.
2007-08-29 14:10:46 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
I could only help with the first one sorry, which is 2z-4+z=z+6.
2007-08-29 14:16:00 · answer #2 · answered by Tosha 1 · 0⤊ 0⤋
get each and all the variables on one area and numbers on the different. 4^x-9 (2^x) =8 I positioned the two on the different area and additionally you may do the alternative element so I did 10-2 which equals 8. 4^x (2^x)=17 extra the 9 to the different area. and then i think locate 4 to some thing capacity and 2 to some thing capacity to get 17. . im no longer likely particular how. .
2016-10-09 10:17:34 · answer #3 · answered by overall 4 · 0⤊ 0⤋