A 74-kg biker accelerates from rest to a final speed v. If the total work done on her during that interval is?

Question

A 74-kg biker accelerates from rest to a final speed v. If the total work done on her during that interval is 3000J, what is v?

Answer 1

using conservation of energy and ignoring friction, the work is converted to kinetic energy
work=.5*m*v^2
3000=.5*74*v^2

solve for v

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