more domain help!!!!!!!!!!!?

Question

what is the domain of the following...?

s(y)=3y/ y=5


f(t)= ^3 square root of t + 4



h(x) = 10 / x^2 -2x



f(s)= suare root of s-1 / s-4



~thank you so much

Answer 1

3y/ y=5

domain= ( - infinity , + infinity) -{0}

f(t)= ^3 square root of t + 4
the domain has to be the set of number when replaced in the function doesn't give u a negative value under the squared root

3(square root of t+4)
domain = [0,+infinity]


h(x) = 10 / x^2 -2x

x^2 -2x=0
x(x-2) =0
x=0 or x-2=0--->x=2

domain is (- infinity , + infinity ) - {0,2}

f(s)= suare root of s-1 / s-4

as for s-1 the domain is [0,infinity)

s-4=0---> x=4
the domain for this is (- infinity , + infinity ) - {4}

so the domain for the function is [0,infinity) - {4}

Answer 2

s(y)=3y/(y+5)
(- infinity
f(t)= ^3 square root of t + 4
Don't understand your notation

h(x) = 10 / (x^2 -2x) = 10/(x(x-2))
x can be any real number except 0 or 2

f(s)= square root of (s-1) / (s-4)
s>4 and s =<1