WHAT iS 63+2X-7-4X
2007-08-29 09:52:26 · 7 answers · asked by PRiNCESS 1 in Science & Mathematics ➔ Mathematics
63+2X-7-4X = 63-7+2X-4X = 56-2X = 2(28-X)
2007-08-29 10:00:28 · answer #1 · answered by Anonymous · 0⤊ 1⤋
63+2X-7-4X
Set the equation equal to zero
63+2X-7-4X = 0
Sort 'like terms'
63-7+2X-4X = 0
Calculate 'like terms'
56-2X = 0
Add 2x to both sides
56 = 2X
Divide by 2 to both sides
56/2 = 2X/2
28 = X
There's your solution!
2007-08-29 10:02:53 · answer #2 · answered by DClegalaide 2 · 0⤊ 0⤋
assuming you mean the above is equal to 0 then 63+28-7-4x=0 which gives 56=2x so x=28
2007-08-29 09:56:36 · answer #3 · answered by adriantheace 4 · 0⤊ 1⤋
just combine like terms:
63+2x-7-4x = (63-7)+(2x-4x) = 56-2x = 2(28-x)
2007-08-29 09:57:17 · answer #4 · answered by grompfet 5 · 0⤊ 1⤋
63 + 2x - 7 - 4x
Combine like terms.
56 - 2x
Divide.
56/-2 = -28.
So the answer is:
x = -28
2007-08-29 10:01:21 · answer #5 · answered by Demenise 2 · 0⤊ 1⤋
Ans: 56 - 2x or 2(28 - x)
2007-08-29 09:59:24 · answer #6 · answered by lenpol7 7 · 0⤊ 1⤋
cont help you unless yoiu give me the =
2007-08-29 09:57:47 · answer #7 · answered by nondescript 6 · 0⤊ 1⤋