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f(x)=(x^2 +16x +164 +6400x^-2 +1600x^-1)^(1/2)

2007-08-29 09:46:59 · 2 answers · asked by DSS 1 in Science & Mathematics Mathematics

2 answers

Use the product and power rules:

If f(x) = g(h(x)), then

f'(x)= g'(h(x))*h'(x)

In your case h(x) = x^2 +16x +164 +6400x^-2 +1600x^-1
And g(x) = (h(x))^(1/2)

From there, just start taking derivatives according to the power rule.

2007-08-29 09:53:42 · answer #1 · answered by Bryan H 2 · 0 0

df/dx = (2x+16 -12800/x^3 - 1600/x^2)/[2*sqrt(x^2 + 16x +6400/x^2+1600/x)]

2007-08-29 16:53:11 · answer #2 · answered by nyphdinmd 7 · 0 0

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