how many Sb atoms are found in 0.43 moles for pure Sb?

Answer 1

Sb(Antimony)
1 mole contains 6.022 x 10^23 atoms - the Avogadro Number.

Therefore 0.43 moles contains
0.43 x 6.022 x 10^23 = 2.58946 x 10^23 atoms(Sb)

Answer 2

It's kind of a trick question. A mole of anything is 6.02 * 10^23 (Avagadro's number). Since your question says it's 0.43 moles of PURE Sb, all you have to do is multiply 0.43 by Avagadro's number to come up with the number of atoms. The trick is that you could ask that question for a pure quantity of ANY element, and all you'd have to do to solve it is multiply the number of moles by 6.02 * 10^23.

Others have already done the math, so you've got the number you need for the solution. I just figured I'd add in some info about **why** that's correct.

Answer 3

0.43 mol sb x 6.022E23 atoms / mol = 2.6E23 atoms sb