find the 100th term and the nth term for 1,3,5,7,9?

Answer 1

nth term = 2*n-1

100th term = 2*100-1 or 199

Answer 2

Assuming u dont know how to obtain the formula, I've shown u the long winded way of obtaining the formula.

1st term : 1 = 1+0 = 1+2(0)
2nd term : 3 = 1+2 = 1+2(1)
3rd term : 5 = 1+4 = 1+2(2)
4th term : 7 = 1+6 = 1+2(3)
.
.
.
nth term : 1+2(n-1)
= 1+2n-2
= 2n-1

Therefore the 100th term,
n=100
100th term = 2(100) - 1 = 199

Hope this helps

Answer 3

This is series of odd numbers
odd numbers are represented by (2n+ 1)
when n= 0 the value is 1, when n = 1, the value is 3
for 100 the term substitute n= 99
2(99) + 1 = 198 + 1 = 199
for n th term substitute n = n-1
2(n-1) + 1 = 2n - 2 + 1 = 2n - 1

Answer 4

This is a series where U(n+1) = U(n) + 2 with U(1) = 1
you know that the series can be written U(n) = U(1) + 2(n-1)
therefore U(100) = 199

Answer 5

the nth term is 2n-1
The 100th term is 2(100)-1 = 199