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how do you resolve this
how can you convert it to standart form?

2007-08-29 03:54:53 · 5 answers · asked by ca481 1 in Science & Mathematics Mathematics

5 answers

There are two components of each term: an integer and a variable. In the first term you have 3 (integer) and "a^2" ("a" is the variable). In the second term you have 12 (integer) and "a" (variable). Now, look at what each term has in common:

Integers: 3 and 12. What do both integers have in common? They both have a multiple of "3". So we will pull a "3" out of each.

Variables: 'a^2' and 'a'. What do these have in common? They both contain atleast one 'a'. So we will pull an 'a' out of each.

So, we pulled a "3" and an "a" out of each:

3a*(a-4)=0

Now break each 'section' up at set that equal to 0 (since anything multiplied by 0 is 0):

1st section: 3a = 0. ANS: a = 0
2nd section (a - 4) = 0. ANS: a = 4.

Therefore you have two answers: a = 0 and 4.

2007-08-29 04:02:02 · answer #1 · answered by miggitymaggz 5 · 1 0

3a^2 - 12a = 0
3a(a - 4) = 0
3a = 0 or
a - 4 = 0
a =0 or 4

2007-08-29 11:05:16 · answer #2 · answered by mohanrao d 7 · 0 0

it can be written as 3a(a-4) = 0
either 3a = 0, or a-4 = 0
a= 0 or 4

2007-08-29 11:06:44 · answer #3 · answered by libraboy28 2 · 0 0

(3a)(a - 4) = 0
a = 0 , a = 4

2007-08-29 11:31:35 · answer #4 · answered by Como 7 · 1 0

factor out the common terms
3a(a-4)=0
divid both sides by 3a
a-4 = 0

2007-08-29 11:01:31 · answer #5 · answered by Anonymous · 0 1

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