3a^2-12a=0?

Question

how do you resolve this
how can you convert it to standart form?

Answer 1

There are two components of each term: an integer and a variable. In the first term you have 3 (integer) and "a^2" ("a" is the variable). In the second term you have 12 (integer) and "a" (variable). Now, look at what each term has in common:

Integers: 3 and 12. What do both integers have in common? They both have a multiple of "3". So we will pull a "3" out of each.

Variables: 'a^2' and 'a'. What do these have in common? They both contain atleast one 'a'. So we will pull an 'a' out of each.

So, we pulled a "3" and an "a" out of each:

3a*(a-4)=0

Now break each 'section' up at set that equal to 0 (since anything multiplied by 0 is 0):

1st section: 3a = 0. ANS: a = 0
2nd section (a - 4) = 0. ANS: a = 4.

Therefore you have two answers: a = 0 and 4.

Answer 2

3a^2 - 12a = 0
3a(a - 4) = 0
3a = 0 or
a - 4 = 0
a =0 or 4

Answer 3

it can be written as 3a(a-4) = 0
either 3a = 0, or a-4 = 0
a= 0 or 4

Answer 4

(3a)(a - 4) = 0
a = 0 , a = 4

Answer 5

factor out the common terms
3a(a-4)=0
divid both sides by 3a
a-4 = 0