solving a Radical equation...help?

Question

2(radical sign over 3) x 5 (radical sign over 6)

Answer 1

2(√3) x 5(√6) =

10√18 =

10√9√2 =

10 x 3 √2 =

30√2

- - - - - s-

Answer 2

2(√3) x 5(√6) =

(multiply 2 by 5...likewise 3 by 6)
10√18 =

(simplify 18 wherein you can get a number with a square root)
10√9√2 =

(square root of 9 is three)
10 x 3 √2 =

(Multiply 10 by 3)
30√2

Thus, the answer is 30 radical sign 2 or 30√2

...Good luck!

Answer 3

2√3 x 5√6

first, multiply the outer numbers which are 2 and 5:
2 x 5 = 10

then multiply √3 and √6:
√3 x √6 = √18

so, we have 10√18

10√18 can still be simplified.. √18 has the factors √9x2

9 has a squareroot which is 3 so we put it out and multiply it ti 10:
10 x 3√2 (2 is left out inside because it has no perfect square)

10 x 3 = 30

so we have,

30√2

By the way, √ means radical sign
=D

Answer 4

30 radical sign over 2

Answer 5

i can't understand it, is it sqrt of 2 over 3 times sqrt of 5 over 6
(sqrt=square root)?