2007-08-29 00:58:49 · 4 answers · asked by whisper2ya 2 in Science & Mathematics ➔ Mathematics
0.2 mL drug + 9.8 mL water
= 0.2 mL drug in a total of 10 mL solution
This is a dilution of 0.2 in 10, or 0.2/10 = 1/50
The dilution factor = 50,
which is the reciprocal of the dilution.
2007-08-29 01:33:52 · answer #1 · answered by falzoon 7 · 1⤊ 0⤋
It's 2%. You are diluting 0.2ml into a TOTAL volume of 10ml, so dilution factor = original volume/ total volume x 100
Addendum:
Falzoon is right. I forgot about the reciprocal.
2007-08-29 08:06:35 · answer #2 · answered by wh 4 · 0⤊ 0⤋
dilution factor=0.2/9.8= 2.04 %
2007-08-29 08:03:04 · answer #3 · answered by shubham_nath 3 · 0⤊ 1⤋
= (0.2 - [0.2 / {9.8 + 0.2}]) / 0.2
= (0.2 - [0.2 / 10]) / 0.2
= (0.2 - 0.02)
= 0.18 / 0.2
= 0.9 or 90%
Answer: 9.8 ml of water is 90% as a dilution factor.
2007-09-02 05:40:22 · answer #4 · answered by Jun Agruda 7 · 3⤊ 0⤋