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(x^3a+1)/ (y^2b-3) * (y^3b+4)/ (x^2a-1)

2007-08-29 00:04:04 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

x^(3a + 1) y^(3b + 4) / y^(2b - 3) x^(2a - 1)
( x^(a + 2) )( y^(b + 7) )

2007-09-02 00:03:41 · answer #1 · answered by Como 7 · 0 0

x^(a+2)y^(b+7)

2007-08-29 08:22:38 · answer #2 · answered by John V 6 · 0 0

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