help with math and factoring polynomials by grouping?

Question

how would you solve:

12x^3+22x^2+6x

i am completely lost. can anyone tell me how to solve it?

excuse me - FACTOR

Answer 1

There is nothing there -to- solve. It isnt a question... it isnt even an equation.

I suggest that you start writing down the entire homework problem... properly.

In fact, I suggest that you quit asking so many questions and start DOING

Every single night... right before your bed time... you come on here and ask every last math homework problem you have. Its no wonder you can never learn the basics.

Answer 2

Hi,

I can only simplify it as a help though.

12x^3+22x²+6x
= 2x (6x² + 11x + 3)

==========================
Answer: 2x (6x² + 11x + 3)
==========================

Hope this helps

Kind regard,
Ryonn

Answer 3

12x^3 + 22x^2 + 6x =
2x(6x^2 + 11x + 3) =
2x(6x^2 + 2x + 9x + 3) =
2x[(6x^2 + 2x) + (9x + 3)] =
2x[2x(3x + 1) + 3(3x + 1)] =
2x[(2x + 3)(3x + 1)].

[Factoring by grouping requires 4 terms. In this problem, I rewrote 11x as (2x + 9x).]

Answer 4

could group stuff so as which you get an issue-unfastened factor, then factor it: (7x³ - 4x²) + (7x - 4) = x²(7x - 4) + (7x - 4) ... have been given problem-unfastened factor (7x - 4) ... now factor: = (7x - 4)(x² + a million) 3x² + x - 2 = (3x² - 2x) + (3x - 2) ... exchange x to -2x + 3x = x(3x - 2) + (3x - 2) ... have been given the problem-unfastened factor ... now factor = (3x - 2)(x + a million) 9x³ - 12x² - 18x + 24 = (9x³ - 18x) - (12x² + 24) = 9x(x² - 2) - 12(x² - 2) = (x² - 2)(9x - 12)

Answer 5

2x^2 (6x+11) + 6x

it's late

Answer 6

2x(6x^2+11x+3x)=0
2x=0 or 6x^2+11x+3x=0
x=0 or (3x+1)(2x+3)=0
x= -1/3 or -3/2