once again I'm working over a problem again and again but the online homework thing keeps rejecting my answer so I turn to you to cheek my numbers.
Two point charges are placed on the x-axis as follows: one positive charge, q1=4.01 nC is located to the right of the origin at .204m. And a second positive charge q2= 4.97 nC and is located to the left of the origin -.302m.
What is the total force (magnitude and direction) exerted by these two charges on a negative point charge q3= -5.99 nC that is placed at the origin?
My answer always comes up at around -2.25 N
2007-08-28 14:32:01 · 1 answers · asked by frozenlint 2 in Science & Mathematics ➔ Physics
Hate to tell you this, but it's +2.25*10^-4N. Opposites attract. The charge to the right may be smaller, but it's closer. Since the force falls off inversely with the square of the distance, this is more important than the slight linear increase in charge of the other one. The force goes to +x. I also did the math, (unfortunately) but at least I can tell you 2.25 is on the money, IF you multiply it by 10^(-4)! (probably the most important part of the answer, 10^-4N is a lot closer than 2.25N).
2007-08-28 14:59:54 · answer #1 · answered by supastremph 6 · 0⤊ 0⤋