2007-08-28 13:34:22 · 6 answers · asked by Fibonacci01123 3 in Science & Mathematics ➔ Mathematics
t^-1
2007-08-28 13:38:03 · answer #1 · answered by John V 6 · 0⤊ 0⤋
(t^2)^-1/2 = t^(-2/2) = t^-1
2007-08-28 20:38:15 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Note the t^(-1) = 1/t
2007-08-28 20:41:12 · answer #3 · answered by tfloto 6 · 0⤊ 0⤋
Just multipy the exponents:
t^(2 * -1/2) = t^(-1)
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2007-08-28 20:42:37 · answer #4 · answered by J S 2 · 0⤊ 0⤋
when you raise an exponent to an exponent, you multiply the two. so it's 2 x (-1/2), so it's -1.
t^-1 is is 1/t.
2007-08-28 20:41:55 · answer #5 · answered by Mr. Jack 3 · 0⤊ 0⤋
(t^m)^(n) = t^(mn)
(t ²)^(-1/2) = t^(-1) = 1 / t
2007-08-29 02:35:10 · answer #6 · answered by Como 7 · 1⤊ 0⤋