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2007-08-28 12:09:23 · 9 answers · asked by kassie 1 in Science & Mathematics Mathematics

9 answers

Well, even imaginary numbers can be irrational or rational.
4i and sqrt(5)*i

And of course, complex numbers can have a rational or irratoinal real or imaginary component.
R + Ri
R + Ii
I + Ri
I + Ii

Keep in mind that even a rational real number is still a complex number.

2007-08-28 12:16:57 · answer #1 · answered by Anonymous · 0 0

Hey there!

Yes. Rational numbers and irrational numbers are a subset, or a part of real numbers. So are integers, and whole numbers.

The only group of numbers, which are not in this group is imaginary numbers, i.e. numbers with i ending in them, like 2i, -3i and so on.

Hope it helps!

2007-08-28 12:22:14 · answer #2 · answered by ? 6 · 0 0

natural numbers: 1,2,3,... whole numbers: natural numbers including 0 integers: 0, 1, -1 ,2, -2,... (whole numbers and their negatives) rational numbers: if a and b are integers (b is not 0) then a/b is a rational numbers real numbers: the completion of the rational numbers (a bit more sophisticated to explain fully) irrational numbers: real numbers that are not also rational numbers, for example √2

2016-05-20 04:08:17 · answer #3 · answered by ? 3 · 0 0

rational and irritional numbers are real number

rational number are ratio numbers or fractions
irritional numbers are numbers which cannot be express as fraction . . . still they can be use in computations

imaginary numbers are not real numbers
that is the difference

2007-08-28 12:17:23 · answer #4 · answered by CPUcate 6 · 0 0

Yes, all numbers are real numbers

2007-08-28 12:26:30 · answer #5 · answered by El 2 · 0 0

real numbers are made up of rational & irrational numbers. There are "uncountably infinitely" many irrational numbers and "countably infinitely" many rational numbers. In fact, they prove in set theory that
the continuum, the 1st "uncountably infinity"
= 2^{"countably infinity"} > "countably infinity"

In set theory, you can keep getting higher and higher orders of infinity!

2007-08-28 12:17:26 · answer #6 · answered by vlee1225 6 · 0 0

Yes.

Imaginary numbers (or complex numbers) have the number " i ", which is the square root of -1, as a component.

2007-08-28 12:13:01 · answer #7 · answered by sharky.mark 4 · 0 0

Yes, they are all real numbers.

2007-08-28 13:08:56 · answer #8 · answered by steiner1745 7 · 0 0

Yes.

Imaginary numbers make up the only nonreals.

2007-08-28 12:13:06 · answer #9 · answered by Chewbacca 3 · 0 0

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