Solve the inequality: (x/2)+(x/3)>5 and solve x>(1/x) and absolute value (x)<1?

Question

Please Show How You Did It

Answer 1

(x/2)+(x/3) = 5x/6 >5, so x > 6
x>(1/x)
if x > 0, we have x^2 > 1 or x > 1
if x < 0, we have x^2 < 1 or -1 < x < 0