2a^2-5a-3
2a^2-6a+a-3
2a(a-3)+1(a-3)
(2a+1)(a-3)
2007-08-28 10:50:14
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answer #1
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answered by lexi 3
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factors: 2a² - 5a + 3 = 0 a² - 5/4a = - 3/2 + (- 5/4)² a² - 5/4a = - 24/sixteen + 25/sixteen (a - 5/4)² = a million/sixteen a - 5/4 = +/- a million/4 = a - 5/4 - a million/4, = a - 6/4, = a - 3/2, = 2a - 3 = a - 5/4 + a million/4, = a - 4/4, = a - a million answer: (2a - 3)(a - a million) Values of a: 2a - 3 = 0, 2a = 3, a = 3/2 a - a million = 0, a = a million answer: a = 3/2, a million
2016-11-13 19:13:28
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answer #2
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answered by valderrama 4
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2
2007-08-28 10:53:33
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answer #3
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answered by THE"IS" 6
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Problem restated correctly:
2a^2 - 5a + 3 = 0
(2a - 3)(a - 1) = 0
Either: 2a - 3 = 0
Then: 2a = 3, a = 3/2
Or: a - 1 = 0
Then: a = 1
Substitute:
Proof: 2 - 5 + 3 = 0
And: 2(3/2)^2 - 5(3/2) + 3
Proof: 4.5 - 7.5 + 3 = 0
2007-08-28 10:58:44
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answer #4
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answered by Robert S 7
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2a^2 - 5a +3
(2a -3)(a - 1)
2007-08-28 10:50:52
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answer #5
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answered by CPUcate 6
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You mean factor?
(a - 1)(2a - 3)
2007-08-28 10:50:13
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answer #6
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answered by Anonymous
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Where's the "equals" sign?
2007-08-28 10:50:36
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answer #7
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answered by Ella 3
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2a^2-5a+3=0
2a^2-2a-3a+3=0
2a(a-1)-3(a-1=0
(a-1)(2a-3)=0
a=1,3/2.ANS
2007-08-28 10:56:34
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answer #8
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answered by Anonymous
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the answer is quite simple........... 1!!!!! duh even I could figure THAT out!!!!!!!!!!
2007-08-28 10:49:47
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answer #9
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answered by Anonymous
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