asume the cards are not replaced.
there are 4 suits. Each suit has 13 cars.
first, the probability of picking one card from a suit is 13/52. After one card is drawn, there is 12 card left in that particular suit. So the probability of picking a second card that is from that same suit is 12/51.
13/52 * 12/51 = 1/17
But, there are 4 suits.
so P = 4 * 1/17 = 4/17
2007-08-28 09:51:30
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answer #1
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answered by 7
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The number of possibilities to choose 2 cards out of 13 ( a suite) is:
13!/(2!*11!) = 13*12/2 = 78
The number of possibilities to choose 2 cards out of 52 is: 52!/(50!*2!) = 51*52/2 = 51*26
The Probability to choose 2 card from the same suite is 4*78/(51*26) = 4*3/51 = 4/17
2007-08-28 09:56:56
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answer #2
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answered by Amit Y 5
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picking one card would leave12 of that suit and 13 each of the other 3. At the start you had 1 chance in 4 of getting any 1 suit now you have12 in 51 or just less than 1 chance in 4 of getting 1 of th same suit on your second try.
2007-08-28 09:58:56
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answer #3
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answered by on my own again 2
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Once any card is picked, there will be 12 remaining cards in the same suit in a deck of 51 remaining cards, so the probability is 4/17.
2007-08-28 09:49:18
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answer #4
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answered by Scythian1950 7
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