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4 answers

asume the cards are not replaced.

there are 4 suits. Each suit has 13 cars.

first, the probability of picking one card from a suit is 13/52. After one card is drawn, there is 12 card left in that particular suit. So the probability of picking a second card that is from that same suit is 12/51.

13/52 * 12/51 = 1/17

But, there are 4 suits.

so P = 4 * 1/17 = 4/17

2007-08-28 09:51:30 · answer #1 · answered by      7 · 0 0

The number of possibilities to choose 2 cards out of 13 ( a suite) is:

13!/(2!*11!) = 13*12/2 = 78

The number of possibilities to choose 2 cards out of 52 is: 52!/(50!*2!) = 51*52/2 = 51*26

The Probability to choose 2 card from the same suite is 4*78/(51*26) = 4*3/51 = 4/17

2007-08-28 09:56:56 · answer #2 · answered by Amit Y 5 · 0 0

picking one card would leave12 of that suit and 13 each of the other 3. At the start you had 1 chance in 4 of getting any 1 suit now you have12 in 51 or just less than 1 chance in 4 of getting 1 of th same suit on your second try.

2007-08-28 09:58:56 · answer #3 · answered by on my own again 2 · 0 0

Once any card is picked, there will be 12 remaining cards in the same suit in a deck of 51 remaining cards, so the probability is 4/17.

2007-08-28 09:49:18 · answer #4 · answered by Scythian1950 7 · 0 0

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