3X^2 +27X + 54
(3X+ ?) (X+?)
I cannot figure this out, what goes where the ? marks are
thanks if you can help. i am taking a college algebra clep test on friday and am studying.
2007-08-28 09:35:42 · 5 answers · asked by Boo Radley 4 in Science & Mathematics ➔ Mathematics
3x^2+27x+54
=3(x^2+9x+18)
=3(x+6)(x+3). ANS.
2007-08-28 09:59:08 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Factoring a tri-nomial is really trial and error.
1) what are the factors of 3? 3 and 1
2) what are the factors of 54? 9 and 6. Note 54 is positive, so 9 and 6 must have the same sign (either both positive, or both negative).
Since the middle term is positive, you can guess they are both positive.
3) TRY: (3x +6 )(x +9 ). Does not work? How about
(3x + 9) (x+6)? Check by distribution or foil.
2007-08-28 09:49:56 · answer #2 · answered by Anonymous · 0⤊ 1⤋
x^2 -- 6x + 9 = 0 or (x -- 3)(x -- 3) = 0 while (x -- 3) = 0 , x = 3 returned while (x -- 3) = 0, x = 3 so x^2 -- 6x + 9 = 0 has 2 same roots x = 3, 3. from quadratic formula a = a million, b = -- 6, c = 9 x = -- b/2a + sqrt{b^2 -- 4ac}/2a, -- b/2a -- sqrt{b^2 -- 4ac}/2a or x = 6/2 + 0, 6/2 -- 0 = 3, 3.
2016-12-16 07:06:27 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Trust me the first guy is right . The answer is
(3x + 9)(x + 6)
2007-08-28 09:50:27 · answer #4 · answered by Gator Girl 5 · 0⤊ 1⤋
3(x + 6)(x + 3)
.
2007-08-28 09:50:21 · answer #5 · answered by Robert L 7 · 1⤊ 0⤋