-2(6y-4)-y= -3(y-3)
=> -12y+8-y= -3y+9
=> -12y-y+3y=9-8
=> -10y=1
=>y= -1/10 ans
2007-08-28 09:36:02
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answer #1
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answered by moona 4
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-2(6y - 4) - y= -3(y - 3)
==> distribute the -2
-12y + 8 - y = -3y + 9
==> subtract 8 from both sides
-12y - y = -3y + 9 - 8
==> add 3y to both sides
-12y - y + 3y = 9 - 8
==> combine like terms on both sides
-10y = 1
==> divide by -10 on both sides
y = -1/10 ... ANSWER
2007-08-28 16:41:50
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answer #2
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answered by C-Wryte 4
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-2(6y - 4) -y = 3(y - 3)
-12y + 8 - y = 3y - 9
-13y + 8 = 3y - 9
-16y = -17
16y = 17
y = 17/16 (1.0625)
2007-08-28 16:40:17
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answer #3
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answered by lenpol7 7
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- 2(6y -4) - y = - 3(y - 3)
- 12y + 8 - y = - 3y + 9
- 12y - y + 3y = 9 - 8
- 10y = 1
y = - 1/10
Answer: y = -1/10
2007-09-01 12:51:27
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answer #4
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answered by Jun Agruda 7
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-2(6y-4)-y=3(y-3)
Multiply -2 with 6y and 4
-12y-8-y=3(y-3)
Multiply 3 with y and -3
-12y-8-y=3y-9
combine -12y and -y
-13y-8=3y-9
subtract -3y from both sides of the equation
-13y-8-3y=-9
add -13y and -3y
-16y-8=-9
add 8 to both sides of the equation
-16y=-1
divide both sides to solve for y by -16
y=-1/-16
Factor out -1 denominator and numerator
y=-1(1)/-1(16)
-1/-1=1
soultion
y=1/16
2007-08-28 16:53:33
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answer #5
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answered by scide i 2
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first distribute to clear the ( )
-12y + 8 - y = -3y + 9
now, combine your y's on one side, constants on the other:
-12y - y + 3y = 9 - 8
-10 y = 1 divide by -10
y = -1/10
2007-08-28 16:37:54
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answer #6
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answered by Marley K 7
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y= -1/10
2007-08-28 16:35:20
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answer #7
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answered by Anonymous
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- 12y + 8 - y = - 3y + 9
8 - 9 = - 3y + 12y + y
- 1 = 10 y
y = - 1 / 10
2007-08-28 17:57:09
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answer #8
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answered by Como 7
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=-12y+8-y=-3y+9
=-12y-y=-3y+17
=-13y=-3y+17
=-16y=17
y=17/-16
For some reason Y didn't come out to a single digit but thats what I got.
2007-08-28 16:46:33
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answer #9
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answered by Heartbreaker 2
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-2(6y-4)-y=-3(y-3)
-12y+8-y=-3y+9
-13y+8=-3y+9
-8............. -8
-13y=-3y+1
+3y +3y
-10y=1
/-10 /-10
y=-1/10
2007-08-28 16:37:17
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answer #10
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answered by Anonymous
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